Find the equation of the circle whose center is at (-10,0) and passes through the point (-6,3)
, Center (h, k): (-10, 0), Point on a circle: (-6, 3), Since the , solve for the radius using the , :, Radius = , (x₁, y₁) = (-10,0), (x₂, y₂) = (-6, 3), Radius = , Radius = , Radius = , Radius = √(25) , Center (h, k): (-10, 0), Radius: 5, (x -(-10))² + (y - 0)² = (5)², x² + 20x + 100 + y² - 25 = 0, x² + 20x + y² + 100 -25 = 0,